How to Design Rock Anchor?
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How to Design Rock Anchor?

22 February 20261 topic
How to Design Rock Anchor?

As geotechnical engineers, we often spend valuable time on repetitive calculations during rock bolt and anchor design. That's why I've developed a free, web-based Rock Bolt Design Calculator to streamline this process!

The Rock Bolt Design Calculator is a free professional geotechnical analysis tool for designing rock bolts and ground anchors based on Australian Standards (AS4678-2002, AS5100).

Through this blog I am trying to explain, how can we design a rock anchor using rock bolt designs calculator.

Design

You are designing rock bolts for a tunnel support system in moderately weathered sandstone. The design must comply with Australian Standards (AS4678-2002, AS5100).

Given Site Data:

  • Rock type: Moderately weathered sandstone
  • Available grout: 32 MPa cement grout
  • Rock-grout bond stress (from pull-out tests): 500 kPa
  • Project category: Category 2 (Normal importance)
  • Proposed bolt: N24 deformed bar (Fu = 168 kN)

Objective: Determine the required bond length for the rock bolt.

Step-by-Step Design Using the Calculator

Step 1: Open the Calculator

Navigate to the Australian tab (default view).

Figure 1 - Rock Bolt Designs Calculator

Step 2: Enter Concrete/Grout Properties

The calculator will automatically compute:

f'ct = 0.36 × √32 = 2.04 MPa (Ultimate anchorage bond strength)

Grout input

Figure 2 - Grout Properties

Step 3: Enter Anchor Properties

Anchor input

Figure 3 - Anchor Properties

Step 4: Enter Drill Hole & Bond Stress Properties

Drill hole input

Figure 4 Drilled hole Parameters

Step 5: Select Reduction Factors

Based on project requirements and AS Standards:

Reduction factors input

Figure 5 - Reduction Factors

Step 6: View Calculated Results

The calculator automatically displays:

Results 1

Results 2

Results 3

Design Summary

Design Decision:

Minimum required bond length = 4.052 m

Adopt L = 4.5 m (with safety margin)

The Grout-Rock interface governs the design because it requires a longer bond length.

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